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Mycamel wrote:
was really only in a solid 10man guild but we never tried to go for bears unfortunately.

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Debuff wrote:
It yields the same thing as his statement, loki.

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Code: Select all

>>> M = [[1,2,3],[4,5,6],[7,8,9]]
>>> G = {sum(row) for row in M}
>>> print(G)
{24, 6, 15}

Code: Select all

>>> M = [[1, 2, 3],
   [4, 5, 6],
   [7, 8, 9]]
G = {sum(row) for row in M}
>>> print(G)
{6, 15, 24}

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Ilarnek wrote:
When working with a 3x3 matrix for example. (Python 3.0)

>>> M = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
>>> {sum(row) for row in M}

outputs:

{24, 6, 15}

I would have expected:

{6, 15, 24}

I was figuring 'row' would start with an index of 0, not an index of 2.

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Code: Select all


>>> M = [[1,2,3],
            [4,5,6],
            [7,8,9]]
>>> {sum(row) for row in M}


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Healzforfree wrote:
it's far cheaper to replace blue quality gems than it is to replace epic quality gems. so for the time being, until i can somehow finagle my set 4 bonus i am working it as best i can.

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